2(x+1)^2=(x-3)(2x+1)

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Solution for 2(x+1)^2=(x-3)(2x+1) equation: 



2(x+1)^2=(x-3)(2x+1)

We move all terms to the left:

2(x+1)^2-((x-3)(2x+1))=0

We multiply parentheses ..

-((+2x^2+x-6x-3))+2(x+1)^2=0



We calculate terms in parentheses: -((+2x^2+x-6x-3)), so:

(+2x^2+x-6x-3)

We get rid of parentheses

2x^2+x-6x-3

We add all the numbers together, and all the variables

2x^2-5x-3

Back to the equation:

-(2x^2-5x-3)



We get rid of parentheses

-2x^2+5x+2(x+1)^2+3=0

We move all terms containing x to the left, all other terms to the right

-2x^2+5x+2(x+1)^2=-3

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